Use The Quadratic Formula To Solve 4x^2+6x=22. Show Your Work And Explain Your Steps.

Use the quadratic formula to solve 4x^2+6x=22. Show your work and explain your steps.

ANSWER :

S = { +(-3 + √97)/4 , -(3 + √97)/4 }

STEP BY STEP EXPLANATION :

4X² + 6X = 22

4X² + 6X = 22

4X² + 6X - 22 = 0

Coefficients:

A = 4 ; B = 6 ; C = -22

Calculating the delta value.

Δ = b² - 4ac

Δ = 6² - 4 × 4 × (-22)

Δ = 36 + 352

Δ = 388

Calculating the roots.

X = (-b ± √Δ)/(2 × a)

X = (-6 ± √388)/(2 × 4)

X = -6 ± 2√97/8

X = -6 ± 2√97/8

X = -3 ± √97/4

X = +(-3 + √97)/4

X = -(3 + √97)/4

Therefore , the solution for quadratic equation is

S = { +(-3 + √97)/4 , -(3 + √97)/4 }

OK.


Comments

Popular posts from this blog

What Is The Length Of The Side Of An Equilateral Triangle If Its Altitude Is 18 Cm?

Variation Problems - Please Solve These For Me. I Need To Pass An Exam!, Exercise 16, 1.\Tthe Force (F) Exerted By An Object Varies Directly As Its Ma